A) \[-1\]
B) \[1\]
C) \[-2\]
D) \[2\]
Correct Answer: B
Solution :
\[{{x}^{2}}+x+1=0\] \[{{x}^{2}}+px+q=0\] \[\alpha +\beta =-1,\alpha \beta =1\]\[\frac{\alpha }{\beta }+\frac{\beta }{\alpha }=-P\] \[-P=\frac{{{(\alpha +\beta )}^{2}}-2\alpha \beta }{\alpha \beta }\frac{{{\alpha }^{2}}+{{\beta }^{2}}}{\alpha \beta }=-P\] \[-P=\frac{1-2}{1}\] \[\Rightarrow \]\[P=1\]You need to login to perform this action.
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