A) \[{{[Fe{{({{H}_{2}}O)}_{6}}]}^{2+}}\]
B) \[{{[Fe(NO){{(CN)}_{5}}]}^{2+}}\]
C) \[{{[Fe{{({{H}_{2}}O)}_{5}}NO]}^{2+}}\]
D) \[{{[Fe({{H}_{2}}O){{(NO)}_{5}}]}^{2+}}\]
Correct Answer: C
Solution :
The brown ring test for \[\text{NO}_{2}^{-}\]and\[\text{NO}_{3}^{-}\] is due to formation of \[{{[Fe{{({{H}_{2}}O)}_{5}}NO]}^{2+}}\]You need to login to perform this action.
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