A) \[0.04\]
B) \[0.02\]
C) \[0.4\]
D) \[0.2\]
Correct Answer: C
Solution :
\[\because \]10 litre of urea solution contains area \[=240gm\] The active mass of urea = ? \[\therefore \] 1 litre of urea solution contains urea \[\frac{240}{10}=24\,gm\] \[\therefore \]Active mass\[=\frac{24}{60}=0.4\] [Mol. wt. of urea\[(N{{H}_{2}}CON{{H}_{2}})\]] \[=14+2+12+16+14+2=60\]You need to login to perform this action.
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