CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2000

  • question_answer
    A force \[\vec{F}=2\vec{i}+\vec{j}-\vec{k}\]acts at a point A whose position vector is \[2\vec{i}-\vec{j}.\] The moment of \[\vec{F}\]about the origin is:

    A)  \[\vec{i}+2\vec{j}-4\vec{k}\]    

    B)  \[\vec{i}-2\vec{j}-4\vec{k}\]

    C)  \[\vec{i}+2\vec{j}+4\vec{k}\]                   

    D)  \[\vec{i}-2\vec{j}+4\vec{k}\]

    Correct Answer: C

    Solution :

    Force \[(\vec{F})=2\vec{i}+\vec{j}-\vec{k}\]and its position vector \[=2\vec{i}-\vec{j}.\] We know that the position vector of a force about origin \[(\vec{r})=(2\vec{i}-\vec{j})-(0\vec{i}+0\vec{j}+0\vec{k})\] or            \[\vec{r}=2\vec{i}-\vec{j}\] Therefore, moment of the force about origin \[=\vec{r}\times \vec{F}=\left| \begin{matrix}    i & j & k  \\    2 & -1 & 0  \\    i & 1 & -1  \\ \end{matrix} \right|=\vec{i}+2\vec{j}+4\vec{k}\]


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