A) \[2AB\]
B) \[2BA\]
C) \[A\div B\]
D) \[AB\]
Correct Answer: C
Solution :
We have \[AB=B\]and \[BA=A\]therefore, \[{{A}^{2}}+{{B}^{2}}=A.A+B.B=A(BA)+B(AB)\] \[=(AB)A+(BA)B\]\[=BA+AB=A+B\]You need to login to perform this action.
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