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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2000

  • question_answer
    A box is lying on an inclined plane what is the coefficient of static friction if the box starts sliding when an angle of inclination is\[{{60}^{o}}\]:

    A) \[1.173\]                             

    B) \[~1.732\]

    C) \[2.732\]                             

    D) \[~1.677\]

    Correct Answer: B

    Solution :

     Angle of inclination \[\theta ={{60}^{o}}\] The formula of the coefficient of static friction \[\mu \] is                 \[\mu =\tan \theta =\tan {{60}^{o}}=\sqrt{3}\] Thus,  \[\mu =1.732\]


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