A) \[10\,\Omega \]should be connected in parallel with A
B) \[10\,\Omega \] should be connected in series with A
C) \[5\,\Omega \] should be connected in series with B
D) \[5\,\Omega \] should be connected in parallel with B
Correct Answer: A
Solution :
Resistance in upper arms \[A=10\,\Omega ;B=5\Omega \] Resistance in lower arm \[C=4\Omega ;D=4\Omega \] The condition required to form a Wheatstone bridge is \[\frac{A}{B}=\frac{C}{D}\]which does not satisfy this case. If a \[10\,\Omega \] resistance is connected in parallel with A [as per option ] The relation for a new resistance is \[\frac{1}{A'}=\frac{1}{10}+\frac{1}{10}=\frac{2}{10}=\frac{1}{5}\] Now the network satisfies the condition of Wheatstone bridge \[\frac{P'}{5}=\frac{R'}{5}or\,\frac{5}{5}=\frac{4}{4}\]You need to login to perform this action.
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