A) 28 N
B) 14 N
C) 50 N
D) 38 N
Correct Answer: A
Solution :
Force required to separate the plates \[F=\frac{2TA}{d}\] Given: area, \[A={{10}^{-2}}{{m}^{2}}\] thickness \[d=0.05\,mm=0.05\times {{10}^{-3}}\,m\] So, \[F=\frac{2\times 10\times {{10}^{-3}}\times {{10}^{-2}}}{0.05\times {{10}^{-3}}}\] \[=28\,N\]You need to login to perform this action.
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