A) zero
B) \[\frac{1}{2}PV\]
C) PV
D) \[2PV\]
Correct Answer: C
Solution :
The work done during the process from P to \[Q=\]area PQRSTP (positive sign is to be taken due to expansion along PQ) Area of triangle PQR + area of rectangle PRST \[=\frac{1}{2}\times 2\times 1+1\times 2=3\,PV\] Work done during process from R to P \[=-\]Area RSTP (negative sign due to compression in atom RP) \[=-ST\times PT=-2\times 1=-2\,PV\] Hence, the work done in the complete cycle \[=3PV-2PV=PV\]You need to login to perform this action.
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