A) 13375 eV
B) 12375 eV
C) 14375 eV
D) 15375 eV
Correct Answer: B
Solution :
Energy of bombarding electron \[E=\frac{hc}{\lambda }\] \[=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{1\times {{10}^{-10}}}\] \[=19.8\times {{10}^{-16}}\,\text{Joule}\] \[=\frac{19.8\times {{10}^{-16}}}{1.6\times {{10}^{-19}}}eV=12375\,eV\]You need to login to perform this action.
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