A) 4
B) 2
C) 1/4
D) ½
Correct Answer: A
Solution :
Conversion of \[\text{A}\xrightarrow{{}}B\]follows second order kinetics therefore, \[r=K{{[A]}^{2}}\] The concentration is doubled \[r=K{{[2A]}^{2}}=K4\,{{[A]}^{2}}\] Therefore, the new rate becomes four times.You need to login to perform this action.
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