A) \[2x+y+4=0\]
B) \[2x-y-12=0\]
C) \[2x+y-4=0\]
D) \[2x-y+4=0\]
Correct Answer: D
Solution :
The equation of curve \[{{x}^{2}}=-4y.\] Differentiating the given equation \[2x=-4\frac{dy}{dx}\Rightarrow \frac{dy}{dx}=-\frac{x}{2}=\frac{4}{2}=2\]the equation of tangent \[y-{{y}_{1}}=\frac{dy}{dx}(x-{{x}_{1}})\] \[y+4=2(x+4)\Rightarrow y+4=2x+8\] \[\Rightarrow \] \[2x-y+4=0\]You need to login to perform this action.
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