A) \[a\]
B) \[b\]
C) zero
D) 1
Correct Answer: C
Solution :
\[0-(x-a)\{0-(x-c)(x+b)\}\] \[+\,(x-b)(x+a)(x+c)=0\] \[(x-a)(x+b)(x-c)\]\[+\,\,(x-b)(x+a)(x+c)=0\] \[2{{x}^{3}}+2acx-2bcx-2abx=0\] \[2x({{x}^{2}}+ac-bc-ab)=0\Rightarrow x=0\]You need to login to perform this action.
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