CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2001

  • question_answer
    The resistors of resistances \[2\Omega ,4\Omega \]and \[8\Omega \] are connected in parallel, then the equivalent    resistance    of    the combination will be:

    A)  \[\frac{8}{7}\Omega \]               

    B)  \[\frac{7}{8}\Omega \]

    C)  \[\frac{7}{4}\Omega \]                                

    D)  \[\frac{4}{9}\Omega \]

    Correct Answer: A

    Solution :

    First resistance \[{{R}_{1}}=2\,\Omega \] Second resistance \[{{R}_{2}}=4\,\Omega \] Third resistance\[{{R}_{3}}=8\,\Omega \]     (given), These three resistances are connected in parallel As the relation for the equivalent resistance of parallel combination is given by \[\frac{1}{R}=\frac{1}{{{R}_{1}}}+\frac{1}{{{R}_{2}}}+\frac{1}{{{R}_{3}}}=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}\] \[=\frac{7}{8}\]                 Thus \[R=\frac{8}{7}\Omega \]


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