A) 2.45 J
B) 4.9J
C) 9.8 J
D) 19.6J
Correct Answer: A
Solution :
Mass of the block\[~m=1\text{ }kg\] Inclination \[\theta ={{60}^{o}}\] Coefficient of friction \[\mu =0.5\] Length of the plane\[d=1\,m\] (given) The force experienced by the body \[F=\mu \,mg\,\cos \theta \] \[=0.5\times 1\times 9.8\times \cos {{60}^{o}}\] \[=4.9\times 0.5=2.45\,N\] Therefore work done \[=F.d=2.45\times 1=2.45\,J\]You need to login to perform this action.
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