A) 2 times
B) 4 times
C) 0.25 times
D) 0.5 times
Correct Answer: B
Solution :
\[C{{H}_{3}}COOH+{{C}_{2}}{{H}_{5}}OH\] \[\xrightarrow{{}}C{{H}_{3}}COO{{C}_{2}}{{H}_{5}}+{{H}_{2}}O\] \[\therefore \] Rate \[\propto [C{{H}_{3}}COOH][{{C}_{2}}{{H}_{5}}OH]\] As per question each solution is diluted with an equal volume of water. Hence the concentration becomes half. So, rate\[=\frac{1}{2}\times \frac{1}{2}\times \text{rate before dilution}\] Therefore, it is clear that the rate decreases four times.You need to login to perform this action.
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