A) 60 g
B) 6 g
C) 4 g
D) 40 g
Correct Answer: B
Solution :
\[1500\,c{{m}^{3}}\]of \[0.\text{1}\,\text{N}\,\text{HCl}\]have number of gm equivalence \[=\frac{{{N}_{1}}\times {{V}_{1}}}{1000}=\frac{1500\times 0.1}{1000}=0.15\] \[\because \] 0.15 gm. equivalent of\[\text{NaOH}\] \[=1.5\times 40=6\,gm.\]You need to login to perform this action.
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