A) ethene
B) ethoxy ethane
C) ethyne
D) ethane
Correct Answer: A
Solution :
\[\underset{\text{Ethanol}}{\mathop{C{{H}_{3}}C{{H}_{2}}OH}}\,\xrightarrow[170{{\,}^{o}}C]{Con.{{H}_{2}}S{{O}_{4}}}\underset{\begin{smallmatrix} \text{Ethylene} \\ \text{(Ethene)} \end{smallmatrix}}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\,\]You need to login to perform this action.
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