A) \[\frac{\pi }{2}\]
B) \[\pi \]
C) \[\pi /4\]
D) none of these
Correct Answer: C
Solution :
\[=\left[ {{\tan }^{-1}}\frac{1}{2}+{{\tan }^{-1}}\frac{1}{3} \right],\] \[{{\tan }^{-1}}x+{{\tan }^{-1}}y={{\tan }^{-1}}\left( \frac{x+y}{1-xy} \right)\] Therefore \[={{\tan }^{-1}}\left[ \frac{\frac{1}{2}+\frac{1}{3}}{1-\frac{1}{2}.\frac{1}{3}} \right]\Rightarrow {{\tan }^{-1}}\left[ \frac{5/6}{5/6} \right]\] \[\Rightarrow \] \[{{\tan }^{-1}}1\] \[=\pi /4\]You need to login to perform this action.
You will be redirected in
3 sec