A) \[(2,0),(-3,0)\]
B) \[(3,0),(4,0)\]
C) \[(1,0),(-1,0)\]
D) \[(1,0),(2,0)\]
Correct Answer: D
Solution :
Equation of circle \[{{x}^{2}}+{{y}^{2}}-3x-4y+2=0\]and it cuts the \[x-\]axis, therefore \[y=0\] \[{{x}^{2}}+0-3x-0+2\Rightarrow {{x}^{2}}-3x+2=0\] \[{{x}^{2}}-2x-x+2=0\] \[\Rightarrow \]\[x(x-2)-1(x-2)=0\] \[\Rightarrow \]\[(x-2)(x-1)=0\Rightarrow x=1,2\] Therefore the points are \[(1,0),(2,0).\]You need to login to perform this action.
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