A) 1/38
B) 1/39
C) 1/6
D) 1/17
Correct Answer: C
Solution :
\[{{T}_{6}}=\frac{1}{61},{{T}_{10}}=\frac{1}{105}\]sixth term are in A.P. \[a+5d=61...(i)\]tenth term are in A.P. \[a+9d=105...(ii)\] Solving (i) and (ii)\[a=6,\]the H.P the first term 1/6You need to login to perform this action.
You will be redirected in
3 sec