A) R/2
B) R/3
C) R/5
D) R/4
Correct Answer: B
Solution :
\[u={{\upsilon }_{e}}/2,\,{{\upsilon }_{e}}=\]escape velocity of body for that planet \[{{h}_{\max }}=\frac{{{u}^{2}}}{2g}R=\] radius of planet \[=\frac{\upsilon _{e}^{2}}{u\times 2g}\] \[g=\]acceleration Due to gravity at that planet .\[=\frac{2Rg}{u\times 2g}{{\upsilon }_{e}}=\sqrt{2\,Rg}\] \[{{h}_{\max }}=R/4\]You need to login to perform this action.
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