A) \[x=6,y=0\]
B) \[y+x-6=0,y-x+6=0\]
C) \[x=0,y=3\]
D) \[x=-6,y=0\]
Correct Answer: A
Solution :
The equation of the tangent at \[(6,0)\]is \[\frac{x{{x}_{1}}}{{{a}^{2}}}+\frac{y{{y}_{1}}}{{{b}^{2}}}=1\Rightarrow \frac{6x}{36}+\frac{y(0)}{9}=1\] \[\frac{6x}{36}=1\Rightarrow x=6\]and the equation of the normal is \[y=0.\]You need to login to perform this action.
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