A) \[\le 9\]
B) \[<9\]
C) \[\ge 9\]
D) \[>9\]
Correct Answer: C
Solution :
Taking \[x=1,y=2\]we get \[\frac{(1+x+{{x}^{2}})(1+y+{{y}^{2}})}{xy}=\frac{3\times 7}{2}>9\] for \[x=1,y=1,\]equality holds \[\therefore \,\,\,\,\ge 9\]You need to login to perform this action.
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