A) \[\pi /3\]
B) \[\pi /2\]
C) \[\pi \]
D) \[\frac{\pi }{2}-x\]
Correct Answer: B
Solution :
Let \[a=1,b=\sin x,c=\cos x\] \[{{b}^{2}}+{{c}^{2}}={{\sin }^{2}}x+{{\cos }^{2}}x=1\Rightarrow {{b}^{2}}+{{c}^{2}}={{a}^{2}}\] \[A=\pi /2.\]You need to login to perform this action.
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