A) \[40{{\,}^{o}}C\]
B) \[~60{{\,}^{o}}C\]
C) \[~0{{\,}^{o}}C\]
D) \[~50{{\,}^{o}}C\]
Correct Answer: C
Solution :
\[{{T}_{1}}=200+273=473{{\,}^{o}}K\] \[{{T}_{2}}=0+273=273{{\,}^{o}}K\] \[{{\mu }_{1}}=1-\frac{{{T}_{2}}}{{{T}_{1}}}=42.2%\] For second \[{{T}_{1}}=0+273=273{{\,}^{o}}K\] \[{{T}_{2}}=-200+273=73{{\,}^{o}}K\] \[{{\mu }_{2}}=1-\frac{{{T}_{2}}}{{{T}_{1}}}\] \[=73.2%\] \[\frac{{{\mu }_{1}}}{{{\mu }_{2}}}=\frac{42.2}{73.2}=\frac{1}{1.73}\] \[{{\mu }_{1}}:{{\mu }_{2}}1:1.73\]You need to login to perform this action.
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