A) 3R
B) 5R
C) R/2
D) R
Correct Answer: D
Solution :
\[{{i}_{1}}=0.9\,\text{amp}\text{.}\] \[{{R}_{1}}=2\Omega \] \[E={{i}_{1}}{{R}_{1}}+{{i}_{1}}r\] ?(i) \[{{R}_{2}}=7\Omega \,{{i}_{2}}=0.3\,\text{amp}\] \[E={{i}_{2}}{{R}_{2}}+r\,{{i}_{2}}\] \[E=0.3\times 7+0.3\,r\] Eq. (i) is equal to eq.(ii) \[0.9\times 2+0.9r=0.3\times 7+9.3r\] \[0.6r=2.1-1.8\] \[r=\frac{0.3}{0.6}\] \[=0.5\,\Omega \]You need to login to perform this action.
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