A) (1, 4)
B) (1, -2)
C) (1, -4)
D) (1, 2)
Correct Answer: C
Solution :
Let \[{{S}_{1}}={{x}^{2}}+{{y}^{2}}+2x-3y+6=0\] \[{{S}_{2}}={{x}^{2}}+{{y}^{2}}+x-8y-13=0\] So, the common chord is given by \[{{S}_{1}}-{{S}_{2}}=0\] \[\therefore \] Common chord is \[({{x}^{2}}+{{y}^{2}}+2x-3y+6)\] \[-({{x}^{2}}+{{y}^{2}}+x-8y-13)=0\] \[2x-x-3y+8y+13+6=0\] \[x+5y+19=0\] and this equation of common chord is satisfied by(1, -4) onlyYou need to login to perform this action.
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