A) 2
B) 1
C) 4
D) 2
Correct Answer: C
Solution :
\[{{(17)}^{2}}=289\] \[\equiv -1\,(\bmod \,5)\] \[{{({{17}^{2}})}^{5}}\equiv {{(-1)}^{15}}(\bmod \,5)\] \[{{17}^{30}}\equiv -1\,\,(\bmod \,5)\] \[i.e.,\] \[{{17}^{30}}=4\,\,(\bmod \,5)\] \[\therefore \] The least remainder when \[{{17}^{30}}\] is divided by 5 is 4.You need to login to perform this action.
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