A) \[\overrightarrow{C}\]
B) \[\overrightarrow{B}\]
C) \[\overrightarrow{B}\times \overrightarrow{C}\]
D) \[\overrightarrow{B}.\overrightarrow{C}\]
Correct Answer: C
Solution :
Since, \[\vec{A}.\vec{B}=0\Rightarrow \vec{A}\bot \vec{B}\] \[\vec{A}.\vec{C}=0\Rightarrow \vec{A}\bot \vec{C}\] \[\Rightarrow \vec{A}\bot \vec{B}\] and \[\vec{A}\bot \vec{C}\] Since, the direction of \[\vec{B}\times \vec{C}\] is \[\bot \] to \[\vec{B}\] and \[\vec{C}\] both i.e., parallel to \[\vec{A}\].You need to login to perform this action.
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