A) \[{{10}^{-6}}V/m\]
B) \[{{10}^{-4}}V/m\]
C) \[{{10}^{-8}}V/m\]
D) \[{{10}^{-2}}V/m\]
Correct Answer: D
Solution :
Given: Specific resistance \[\rho ={{10}^{-7}}\Omega -m\],\[A={{10}^{-6}}{{m}^{2}},\,i=0.1\,A\] Resistance of 1 metre length of wire \[R=\frac{\rho l}{A}=\frac{\rho \times 1}{A}={{10}^{-7}}/{{10}^{-1}}\Omega \] \[\therefore \] potential gradient = potential drop per unit length \[K=Ri={{10}^{-1}}\times 0.1={{10}^{-2}}\] volt/metreYou need to login to perform this action.
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