A) \[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}\]
B) \[ZnS{{O}_{4}}\]
C) \[MgS{{O}_{4}}\]
D) \[SnC{{l}_{2}}\]
Correct Answer: C
Solution :
This salt is \[MgS{{O}_{4}}\]. It is soluble in dilute \[HCl\]. With \[NaOH\], it gives white precipitate of magnesium hydroxide, which is insoluble in excess of\[NaOH\]. \[MgS{{O}_{4}}+2HCl\xrightarrow{{}}MgC{{l}_{2}}+{{H}_{2}}S{{O}_{4}}\] \[MgS{{O}_{4}}+2NaOH\xrightarrow{{}}Mg{{(OH)}_{2}}\downarrow +N{{a}_{2}}S{{O}_{4}}\] \[Mg{{(OH)}_{2}}+NaOH\xrightarrow{{}}\times \] (No reaction) While other hydroxides form soluble salts,\[NaAl{{O}_{2}},\,N{{a}_{2}}Zn{{O}_{2}}\] and \[N{{a}_{2}}Sn{{O}_{2}}\] respectively.You need to login to perform this action.
You will be redirected in
3 sec