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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2003

  • question_answer
    A colour less crystalline salt \[x\] is soluble in dilute \[HCl\]. On adding \[NaOH\] solution, it gives a white precipitate which is insoluble in excess of \[NaOH\]. \[x\] is :

    A)  \[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}\]                             

    B)  \[ZnS{{O}_{4}}\]

    C)  \[MgS{{O}_{4}}\]                           

    D)  \[SnC{{l}_{2}}\]  

    Correct Answer: C

    Solution :

    This salt is \[MgS{{O}_{4}}\]. It is soluble in dilute \[HCl\]. With \[NaOH\], it gives white precipitate of magnesium hydroxide, which is insoluble in excess of\[NaOH\]. \[MgS{{O}_{4}}+2HCl\xrightarrow{{}}MgC{{l}_{2}}+{{H}_{2}}S{{O}_{4}}\] \[MgS{{O}_{4}}+2NaOH\xrightarrow{{}}Mg{{(OH)}_{2}}\downarrow +N{{a}_{2}}S{{O}_{4}}\] \[Mg{{(OH)}_{2}}+NaOH\xrightarrow{{}}\times \] (No reaction) While other hydroxides form soluble salts,\[NaAl{{O}_{2}},\,N{{a}_{2}}Zn{{O}_{2}}\] and \[N{{a}_{2}}Sn{{O}_{2}}\] respectively.


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