A) \[50\times {{10}^{-3}}sec\]
B) \[5\times {{10}^{-3}}sec\]
C) \[1\times {{10}^{-3}}sec\]
D) \[2\times {{10}^{-3}}sec\]
Correct Answer: B
Solution :
The time taken by a.c in reaching from zero to maximum value is \[t=\frac{T}{4}=\frac{T}{4f}=\frac{1}{50\times 4}=5\times {{10}^{-3}}\sec \]You need to login to perform this action.
You will be redirected in
3 sec