A) \[{{e}^{-a}}\]
B) e
C) \[{{e}^{a}}\]
D) 1
Correct Answer: A
Solution :
We have \[=\underset{x\to 0}{\mathop{\lim }}\,\,{{(1-ax)}^{1/x}}\] \[\underset{x\to 0}{\mathop{\lim }}\,\,{{(1-ax)}^{-\frac{1}{ax{{]}^{-a}}}}}\] \[={{e}^{-a}}\] \[\left[ \underset{x\to 0}{\mathop{\lim }}\,\,\,{{(1-ax)}^{\frac{1}{-ax}}}=e \right]\]You need to login to perform this action.
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