A) \[{{F}_{1}}=3N,{{F}_{2}}=5N,\,{{F}_{3}}=1N\]
B) (b \[{{F}_{1}}=3N,{{F}_{2}}=5N,\,{{F}_{3}}=9N\]
C) \[{{F}_{1}}=3N,{{F}_{2}}=5N,\,{{F}_{1}}=6N\]
D) \[{{F}_{1}}=3N,{{F}_{2}}=5N,\,{{F}_{3}}=15N\]
Correct Answer: C
Solution :
For the equilibrium of forces, resultant force must be zero. Hence, sum of two smaller forces must be greater than third (large) force so that, closed triangle can be formed. Hence, \[{{F}_{1}}(3N)+{{F}_{2}}(5N)>{{F}_{3}}(6N)\]
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