A) 6
B) 1
C) -1
D) -5
Correct Answer: D
Solution :
We have \[\underset{x\to a}{\mathop{\lim }}\,=\frac{f(a)\,g(x)-f(x)g(a)}{x-a}\] As we see it is \[\frac{0}{0}\] form so applying L-Hospital rule we have \[\underset{x\to a}{\mathop{\lim }}\,=\frac{f(a)g(x)-f(x)g(a)}{1-0}\] \[=f(a)g\,(a)-f\,(a)\,g\,(a)\] \[=2(-1)-1\,(3)=-2-3=-5\]You need to login to perform this action.
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