A) 40 V
B) - 40 V
C) 300 V
D) 140 V
Correct Answer: A
Solution :
The induced e.m.f \[e=-\frac{d\phi }{dt}\] So, \[e=-\frac{d}{dt}\,(5{{t}^{3}}-100\,t+300)\] or \[e=-(15\,\,{{t}^{2}}-100)\] Induced e.m.f at \[t=2\,\,\sec \] \[e=-(15\times 4-100)=+40\] voltYou need to login to perform this action.
You will be redirected in
3 sec