A) 152
B) 56
C) 168
D) 68
Correct Answer: C
Solution :
Atomic weight of element, M = equivalent weight x valency \[=20\times 3\] = 60 Molecular formula of its oxide \[={{M}_{2}}{{O}_{3}}\] Hence, molecular weight of oxide \[=2\times 60+3\times 12\] = 120 + 48You need to login to perform this action.
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