A) \[\left[ \begin{matrix} 1 & 3 \\ 2 & -1 \\ \end{matrix} \right]\]
B) \[\left[ \begin{matrix} 1 & -3 \\ 2 & -1 \\ \end{matrix} \right]\]
C) \[\left[ \begin{matrix} 2 & 6 \\ 4 & -2 \\ \end{matrix} \right]\]
D) \[\left[ \begin{matrix} 2 & -6 \\ 4 & -2 \\ \end{matrix} \right]\]
Correct Answer: A
Solution :
Given that, \[2X+\left[ \begin{matrix} 1 & 2 \\ 3 & 4 \\ \end{matrix} \right]=\left[ \begin{matrix} 3 & 8 \\ 7 & 2 \\ \end{matrix} \right]\] It can be written as, \[2X=\left[ \begin{matrix} 3 & 8 \\ 7 & 2 \\ \end{matrix} \right]-\left[ \begin{matrix} 1 & 2 \\ 3 & 4 \\ \end{matrix} \right]\] or \[2X=\left[ \begin{matrix} 3-1 & 8-2 \\ 7-3 & 2-4 \\ \end{matrix} \right]\] or \[2X=\left[ \begin{matrix} 3 & 6 \\ 4 & -2 \\ \end{matrix} \right]=2\left[ \begin{matrix} 1 & 3 \\ 2 & -1 \\ \end{matrix} \right]\] \[\Rightarrow \] \[X=\left[ \begin{matrix} 1 & 3 \\ 2 & -1 \\ \end{matrix} \right]\]You need to login to perform this action.
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