A) \[\frac{5}{3}\]
B) \[\frac{5}{4}\]
C) \[\frac{5}{12}\]
D) \[\frac{12}{5}\]
Correct Answer: C
Solution :
Solving \[y=\sqrt{x}\]or\[{{y}^{2}}=x,\,(y\ge 0)\] and \[y={{x}^{3}}\]we get points of intersection (0, 0) and (1, 1) \[\therefore \] Required area \[=\int_{0}^{1}{(\sqrt{x}-{{x}^{3}})dx}\]\[=\frac{5}{12}\] sq. unitsYou need to login to perform this action.
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