A) 4
B) 6
C) 20
D) \[\sqrt{20}\]
Correct Answer: D
Solution :
Centre is point of intersection of two diameters i.e., the point is C (8, - 2) \[\therefore \] \[r=CP=\sqrt{4+16}=\sqrt{20}\] \[=2\sqrt{5}\]You need to login to perform this action.
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