A) -2
B) 0
C) 2
D) 4
Correct Answer: C
Solution :
We have, \[I+\int_{-1}^{1}{|1-x|\,dx}\] here, \[-1\le x\le 1\Rightarrow 1-x\ge 0\] \[\therefore \] \[I=\int_{-1}^{1}{(1-x)\,dx}\] \[={{\left[ x-\frac{{{x}^{2}}}{2} \right]}^{1}}\] \[=1-\frac{1}{2}+\frac{1}{2}+1=2\]You need to login to perform this action.
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