A) 0.5 A
B) 0.25 A
C) 2 A
D) 1 A
Correct Answer: A
Solution :
At the neutral point, the magnetic field produced by the magnet becomes equal and opposite to some other magnetic field. This other magnetic field is actually the horizontal component of earths magnetic field. Magnetic field at the centre of circular coil \[{{B}_{H}}=\frac{{{\mu }_{0}}}{4\,\pi }\frac{2\pi \,nI}{r}\] \[I\] and r being the current and radius of circular coil respectively. or \[I=\frac{4\,\pi }{{{\mu }_{0}}}\frac{r{{B}_{H}}}{2\pi n}\] \[=\frac{{{10}^{7}}\times 0.1\times 0.314\times {{10}^{-4}}}{2\times 314\times 10}\] \[=0.5\,A\]You need to login to perform this action.
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