question_answer

For the ellipse\[24{{x}^{2}}+9{{y}^{2}}-150x-90y+225=0\] the eccentricity e is equal to :

A)  \[\frac{2}{5}\]                                  

B)  \[\frac{3}{5}\]

C)  \[\frac{4}{5}\]                                  

D)  \[\frac{1}{5}\]