A) fluorine
B) iodine
C) chlorine
D) bromine
Correct Answer: B
Solution :
Nitric acid oxidise iodine into iodic acid\[(HI{{O}_{3}})\].\[10HN{{O}_{3}}+{{I}_{2}}\underset{Iodic\text{ }acid}{\mathop{\xrightarrow{{}}3HI{{O}_{3}}+10NN{{O}_{2}}}}\,+4{{H}_{2}}O\]You need to login to perform this action.
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