A) 1, 2, 2
B) 2, 2, 1
C) 1, 1, 2
D) 2, 1, 2
Correct Answer: C
Solution :
\[{{N}_{2}}\,\,\,+\,\,\,\,3{{H}_{2}}2N{{H}_{3}}\]Initial | \[\frac{56}{28}=2\] | \[\frac{8}{2}=4\] | |
At equilibrium | \[\underset{mol}{\mathop{(2-x)}}\,\] | \[\underset{mol}{\mathop{(4-3x)}}\,\] | \[2x=\frac{34}{17}=2\,mol\] |
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