A) ethyl benzoate
B) ethyl formate
C) ethyl acetate
D) methyl acetate
Correct Answer: A
Solution :
The reaction occurs as follows : \[\underset{ethyl\text{ }benzoate}{\mathop{{{C}_{6}}{{H}_{5}}COO{{C}_{2}}{{H}_{5}}}}\,+KOH\xrightarrow{\Delta }{{C}_{6}}{{H}_{5}}COOK\] \[+{{C}_{2}}{{H}_{5}}OH\] \[{{C}_{6}}{{H}_{5}}COOK+HCl\to \underset{white\text{ }solid}{\mathop{{{C}_{6}}{{H}_{5}}COOH+KCl}}\,\]You need to login to perform this action.
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