A) 16
B) - 16
C) \[16\,\omega \]
D) \[16\,{{\omega }^{2}}\]
Correct Answer: C
Solution :
Given that, \[\omega =\frac{-1+\sqrt{3}\,i}{2}\] \[\therefore \] \[{{(3+\omega +3\,{{\omega }^{2}})}^{4}}\] \[={{\left[ 3+\left( \frac{-1+\sqrt{3}\,i}{2} \right)+{{\left( \frac{-1+\sqrt{3\,i}}{2} \right)}^{2}} \right]}^{4}}\] \[=16\,\omega \]You need to login to perform this action.
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