A) 1
B) 2
C) 3
D) 4
Correct Answer: B
Solution :
Given that, \[{{(1+i)}^{2n}}={{(1-i)}^{2n}}\] \[\Rightarrow \] \[{{(1-1+2i)}^{n}}={{(1-1-2i)}^{n}}\] \[{{2}^{n}}\,{{i}^{n}}={{2}^{n}}\,{{(-1)}^{n}}\,{{i}^{n}}\] \[1={{(-1)}^{n}}\] \[\therefore \] The smallest value of n is 2.You need to login to perform this action.
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